The straight line through two points will have an equation in the form \(y = mx + c\). Then, we can find the value of \(c\), the \(y\)-intercept, by substituting the coordinates of one point into the ...
The straight line through two points will have an equation in the form \(y = mx + c\). We can find the value of \(m\), the gradient of the line, by forming a right-angled triangle using the ...
Find \(\ds \lim_{h\to 0}\frac{f(1+h)-f(1)}{h}\) where \(\ds f(x)=\frac{3x+1}{x-2}\text{.}\) What does the result in (a) tell you about the tangent line to the graph ...